Question

a
$4a2 + 6a + 2 = 0$

Answer 1

$4 {a}^{2} + 6a + 2 = 0 \\ 4 {a}^{2} + 4a + 2a + 2 = 0 \\ 4a(a + 1) + 2(a + 1) = 0 \\ (4 a + 2)(a + 1) = 0 \\ a = - \frac{2}{4} = - \frac{1}{2} \\ a = - 1.$
Hope it may help you...



Thank you..

Answer 2

hay!!

4a²+6a+2=0

=> 4a²+4a+2a+2=0

=> 4a(a+1)+2(a+1)

=> (4a+2) (a+1)

=>> 4a+2=0
=> 4a=-2
=> a=-2/4
=> a=-1/2

=>>a+1=0
=> a=-1




I hope it's help you