Question

a
${6x}^{ 5} + 11x {}^{4 } - 33x {}^{2 } + 11x + 6 = 0$
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Answer 1

Answer:

Step by step solution :

STEP

1

:

Equation at the end of step 1

(((((6•(x5))+(11•(x4)))-(33•(x3)))-(3•11x2))+11x)+6 = 0

STEP

2

:

Equation at the end of step

2

:

(((((6•(x5))+(11•(x4)))-(3•11x3))-(3•11x2))+11x)+6 = 0

STEP

3

:

Equation at the end of step

3

:

(((((6•(x5))+11x4)-(3•11x3))-(3•11x2))+11x)+6 = 0

STEP

4

:

Equation at the end of step

4

:

(((((2•3x5) + 11x4) - (3•11x3)) - (3•11x2)) + 11x) + 6 = 0

STEP

5

:

Trying to factor by pulling out

5.1 Factoring: 6x5+11x4-33x3-33x2+11x+6

Thoughtfully split the expression at hand into groups, each group having two terms :

Group 1: -33x3-33x2

Group 2: 6x5+11x4

Group 3: 11x+6

Pull out from each group separately :

Group 1: (x+1) • (-33x2)

Group 2: (6x+11) • (x4)

Group 3: (11x+6) • (1)

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