Question

a
${a}^{4} \times b \: - {3a}^{2} {b}^{2} - 6a {b}^{3}$
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Answer 1

Answer:Without expanding , find the value of  

∣

∣

∣

∣

∣

∣

∣

∣

​  

 

a+b

2a+b

4a+b

​  

 

2a+b

3a+b

5a+b

​  

 

3a+b

4a+b

6a+b

​  

 

∣

∣

∣

∣

∣

∣

∣

∣

​  

 

Q2

Solve:

(3a−b)  

2

−4(3a−b)+4

Q3

Simplify :

(a  

4

 - 3a  

2

 + 6a - 8) - (a  

4

 - 10a + 4a  

2

 + 8)

Step-by-step explanation: