A text book of mathematics costs 2 rupees more than a text book of literature .If 5 litrature books cost 38 rupees more than 3 mathematics books, what is the cost of each literature book?
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1
Hey, here is your answer...
Let the cost of 1 mathematics book be ₹x and 1 literature book be ₹y. x=y+2
So, according to your question,
38+3x=5y
38+3(y+2)=5y
38+3y+6=5y
44=2y
y=₹22
So, x=₹24.
Hope it helps you...
Plzzz mark as brainliest...
Let the cost of 1 mathematics book be ₹x and 1 literature book be ₹y. x=y+2
So, according to your question,
38+3x=5y
38+3(y+2)=5y
38+3y+6=5y
44=2y
y=₹22
So, x=₹24.
Hope it helps you...
Plzzz mark as brainliest...
Answered by
5
Solution :
Let the literature book = x
Maths book = y
Cost of textbook of maths is 2 rupees more than that of a literature book, y = x + 2 ......(1)
Cost of 5 literature books = 5x
38 rupees more than 3 books,
5x = 3y + 38 ......(2)
Equating (1) and (2) we get :
x + 2 = y × 3
5x - 38 = 3y
3x + 6 = 3y ......(3)
Equating (1) and (3) we get :
3x + 6 = 3y
5x - 36 = 3y
- + -
___________
-2x = -4
___________
x =
x = 22
Therefore, cost of each literature book is 22 rupees.
Let the literature book = x
Maths book = y
Cost of textbook of maths is 2 rupees more than that of a literature book, y = x + 2 ......(1)
Cost of 5 literature books = 5x
38 rupees more than 3 books,
5x = 3y + 38 ......(2)
Equating (1) and (2) we get :
x + 2 = y × 3
5x - 38 = 3y
3x + 6 = 3y ......(3)
Equating (1) and (3) we get :
3x + 6 = 3y
5x - 36 = 3y
- + -
___________
-2x = -4
___________
x =
x = 22
Therefore, cost of each literature book is 22 rupees.
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