a textbook of mathematics cost 2 rupees more than a textbook of literature.If 5 literature book contains 38 rupees more than 3 mathematics book,what is the cost of each literature book?
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Solution :
Let the literature book = x
Maths book = y
Cost of textbook of maths is 2 rupees more than that of a literature book, y = x + 2 ......(1)
Cost of 5 literature books = 5x
38 rupees more than 3 books,
5x = 3y + 38 ......(2)
Equating (1) and (2) we get :
x + 2 = y × 3
5x - 38 = 3y
3x + 6 = 3y ......(3)
Equating (1) and (3) we get :
3x + 6 = 3y
5x - 36 = 3y
- + -
___________
-2x = -4
___________
x =
x = 22
Therefore, cost of each literature book is 22 rupees.
Let the literature book = x
Maths book = y
Cost of textbook of maths is 2 rupees more than that of a literature book, y = x + 2 ......(1)
Cost of 5 literature books = 5x
38 rupees more than 3 books,
5x = 3y + 38 ......(2)
Equating (1) and (2) we get :
x + 2 = y × 3
5x - 38 = 3y
3x + 6 = 3y ......(3)
Equating (1) and (3) we get :
3x + 6 = 3y
5x - 36 = 3y
- + -
___________
-2x = -4
___________
x =
x = 22
Therefore, cost of each literature book is 22 rupees.
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