Question

(a) The angles of depression of top and bottom of a building from the top of a tower are 35° and 60°
respectively. If the height of the building is 20 m, find the height of the tower​

Answer 1

Answer:

Let AB=height of the building=100m

DE=AC=AB+BC=h= height of the tower

∠ADC=60

∘

∠BDC=60

∘

Now

tan30

∘

=

CD

CB

=

d

x

3

1

=

d

x

(1)

tan60

∘

=

CD

CA

=

d

x+100

3

=

d

x+100

(2)

From (1)

d=

3

x (3)

Substituting (3) in (2)

3

=

3

x

(x+100)

3x=x+100

2x=100

x=50

Height of the tower=DE=h=AB+CB=100m+x=100m+50m=150m

solution

Answer 2

Step-by-step explanation:

x=h

x=sqrt(3)×(h-20)

h=sqrt(3)× (h-20)

h=47.45m

hope this helps