a) The angles subtended by chords AC and CB at the centre O measure 90 and 116", respectively. Find the measure of ZBCA.
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Answer:
OA=OB=OC=radius
In △OBC
Since OB=OC
∠OBC=∠OCB
∠BOC=155
∠OBC+∠OCB+∠BOC=180
2∠OCB=180−155
∠OCB=12.5
Similarly in △OAC
2∠OCA=180−55
∠OCA=62.5
2∠OCB=180−155
∠OCB=12.5
SCB = 2∠OCB=180−155
∠OCB=12.5
OCB + 2∠OCB=180−155
∠OCB=12.5
∘
OCA=12.5+62.5=75
∘
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Answer:
O measure 90 and 116", respectively. Find the measure of ZBCA.
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