(a) The area of a rhombus is 120 m square. If one of the diogonals is 24 m, find the perimeter of the rhombus. (b) The sides of a rhombus are 5 cm each and one diagonal is 8 cm. Calculate (1) The length of the other diagonal, and (2) the area of the rhombus
Answers
Answer:
a). perimeter = 50.4 m
b). 1) length of the other diagonal = 6cm
2). area of the rhombus = 48 m²
Step-by-step explanation:
Formula
1). Area of rhombus = d₁d₂ (if d₁ and d₂ are 2 diagonals)
2). For right angled triangle
Hypotenuse² = base² + height²
The figure attached with this answer shows the 2 rhombus.
a)It is given that, The area of a rhombus is 120 m square. If one of the diagonals is 24 m
Find the length of other diagonal
d₁ = 24
Area of rhombus = d₁d₂ = 120 m²
d₂ =120/ d₁ = 120 24 = 5 m
To find the side of rhombus
From the figure 1) we get triangle AOB is right triangle and
AO = 24/2 = 12 and BO = 5/2 = 2.5
AB² = AO² + BO²
AB² = 12² + 2.5² = 144 + 6.25 = 150.25
AB = √150.25 =12.26m
Find the perimeter
Perimeter of rhombus = 4*side = 4 * 12.26 = 50.4 m
b). It is given that, The sides of a rhombus are 5 cm each and one diagonal is 8 cm.
1). Find the length of the other diagonal
From the figure b) we get CD = 5cm and CO = 8/2 = 4 cm
ΔCOD is right triangle we get,
OD² = CD² - CO²
OD² = 5² - 4² = 9
OD = 3
Therefore length of other diagonal = 2*OD = 2* 3 = 6 cm
2). Area of rhombus
d₁ = 8cm and d₂ = 6cm
Area of rhombus = d₁d₂ = 8*6 = 48 m²
Answer:
bhai me ne bhi google me likha to tera javab aya