Question

(a) The area of pistons in hydraulic machine are 6 cm2 and 576 cm2. What force on the smaller piston will support a load of 1152 N on the larger piston? State the assumption made in the above calculation. six cm square and 576 cm squar

Answer 1

Answer:

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Answer 2

$F_1=12\ N$ is the force required on the smaller piston to support the given load on assuming that there is no frictional loss and the fluid is incompressible.

Explanation:

Given:

area of smaller piston, $A_1=6\ cm^2$

area of large piston, $A_2=576\ cm^2$

load on the larger piston, $F_2=1152\ N$

Using Pascal's law:

(It states that any change in pressure at any point in a confined incompressible fluid is transmitted throughout the fluid volume at its each point.)

$P_1=P_2$

$\frac{F_1}{A_1} =\frac{F_2}{A_2}$

$\frac{F_1}{6} =\frac{1152}{576}$

$F_1=12\ N$

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TOPIC: Pascal's Law

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