Question

a) the area of the ∆ ABC,
(b) the length of AC and
(c) the length of the altitude drawn from B to AC​

Answer 1

Answer:

In triangle ABC , Base = 5cm , Height = 12cm

$area \: of \: triangle = \frac{1}{2} \times base \: \times height \\ \: \: = \frac{1}{2} \times 12 \times 5 \\ = 30 {cm}^{2}$

2 ) Triangle ABC is a right angled triangle

Therefore, by Pythagoras Theorem,

AC ^2 = AB^2 + BC^2

=144 + 25

=169

AC = 13cm ... taking square roots on both sides

3) In right angled triangle ABC,

Median BM is drawn to Hypotenuse AC

We know, median drawn in a right angled triangle is half of Hypotenuse

Therefore,

$BM= \frac{1}{2} \times 13 = 6.5cm$

Step-by-step explanation:

I hope this helps you :)