Question

A
The bottom of the ladder is 4 metres away from the wall.
bles. In the adjoining figure, it is given that PR LOS,PO = 15 cm, PS - 13 cm. RS = 5 cm.
Find (1) PR (ii) OR (iii) OS.​

Answer 1

$\huge \underline{\underline{\sf{ \color{darkblue}{✒ANSWER:-} }}}$

pr = 13 c.m = hypotenuse

qp = 12 c.m

here, by Pythagoras theorem

$pr^{2} =pq^{2}+qr^{2}$

$13^2 = x^2 + 12^2$

$169 - 144 = x^2$

$X^2 = 25$

$x = 5 \: \: \: c.m$

$tan \: \: p - cot \: \: r = 5/12 - 5/12$

$tan \: \: p - cot \: \: \: r = 0.$

Answer 2

Answer:

See it

Step-by-step explanation:

Other values you can calculate similarly of OR and OS.