Math, asked by kumarlopinti85, 1 month ago

a) The cost of manufacturing a car is made up of three items : cost of material, labour, overheads. In a year, the cost of these items were in the ratio 4:3:2. Next year the cost of material rose by 10%, cost of labour increased by 8% but the overheads reduced by 5%. Find the increase percentage in the price of the car. ​

Answers

Answered by upaydiya078
0

Answer:

before increase total cost = 4+3+2=9,

after increasing the cost = 9.54

so increase of .54 over 9 , equal to 6%

Answered by AadilPradhan
0

The increase percentage in the price of the car is 6%.

Given:

The cost of manufacturing a car is made up of three items : cost of material, labour, overheads. In a year, the cost of these items were in the ratio 4:3:2. Next year the cost of material rose by 10%, cost of labour increased by 8% but the overheads reduced by 5%.

To find:

Find the increase percentage in the price of the car. ​

Solution:

Let the cost of the car be Rs. x

Then,

sum of ratio = 4 +3+2 = 9

Material costs = ratio of material/ sum of ratio * total cost of car = 4/5 * 9

Similarly,

Labour costs = 3x/9

Overhead costs = 2x/9

New material costs = Original cost + 10% of original cost = 4x/9 + 10% of 4x/9

= 4x/9 + 10/100 * 4x/9 = 4x/9 + 4x/90

= (40x + 4x)/90

= 44x/90

New labour costs = Original cost + 8% of original cost = 3x/9 + 8% of 3x/9

= 1x/3 + 8/100 * 1x/3 = x/3 + 8x/300

= (100x + 8x) / 300

= 108x/300 = 36x/100

New overhead costs =  Original cost - 5% of original cost = 2x/9 - 5% of 2x/9

= 2x/9 - 5/100 * 2x/9 = 2x/9 - 10x/900

= 2x/9 - x/90

= (20x - x) / 90

=19x/90

Increase in the cost of T.V. = New cost - original cost of each cost

= (44x/90 - 4x/9) + (36x/100 - 3x/9) + (19x/90 - 2x/9)

= 4x/90 + 2x/75 - x/90  [because cost of overheads were reduced]

= (20x+12x-5x)/450

= 27x/450 = 3x/50

∴Increase in cost= increase in cost/original cost * 100

= (3x/50)/x * 100

x will be canceled as numerator and denominator

= 3/50 * 100

= 3 * 2 = 6%

#SPJ2

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