Question

(a) The distance covered by a particle in timetis given byx=a+bt+ct+dt';
find the dimensions of a, b, c, d.​

Answer 1

Answer:

Given that,

x=a+bt+ct2+dt3

x is the displacement.

Now, by principle of homogeneity

a=bt=ct2=dt3=x

Now, a=L

  [bt]=[L]

 b=[LT−1]

c=[LT−2]

d=[LT−3]

Hence, the dimension of a, b, c and d is [L],[LT−1],[LT−2]and[LT−3]

Explanation:

hope it will hlp u

Answer 2

Answer:

Hi nitashsree how are you .