Question

a) The figure (i) given below shows a solid of uniform cross-section. Find the ve
of the solid. All measurements are in cm and all angles in the figure are
angles.
(b) The figure (ii) given below shows the cross-section of a concrete wall
constructed. It is 2 m wide at the top, 3.5 m wide at the bottom and its he
6 m, and its length is 400 m. Calculate (i) the cross-sectional area, and (ii) v
of concrete in the wall.
(c) The figure (iii) given below show the cross-section of a swimming pool
broad, 2 m deep at one end and 3 m deep at the other end. Calculate the v
of water it will hold when full, given that its length is 40 m.​

Answer 1

Answer:

ANSWER

The image consists of two cuboids. When we subtract the volume of smaller cuboid from the larger cuboid, we will get the volume of the desired cuboid.

volume of cuboid=length∗breadth∗height

Dimensions of larger cuboid

length=4 cm

breadth=9 cm

height=9 cm

volume=4∗9∗9=324

Dimensions of smaller cuboid

length=4 cm

breadth=6 cm

height=6 cm

volume=4∗6∗6=144

volume of desired cuboid=volume of larger cuboid−volume of smaller cuboid

volume of desired cuboid=324−144=180 cm

3

solution

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