Question

a. The first and the last terms of an AP are (– 4) and 146 respectively and the sum of the AP is 7171. Find the

number of terms in the AP and the common difference.​

Answer 1

A1=-4

an=146

Sn=7171

an=a+(n-1)d

150=(n-1)d

7171=n/2(2a+(n-1)d)

101=n

no. of terms are 101

d

150=(n-1)d

put value of n

d=3/2...