A.
The initial velocity of a particle moving along x-axis-
is u (at t = 0 and x = 0) and its acceleration a is
given by a = kx. Which of the following equation is
correct between its velocity (V) and position (x)?
Answers
Answered by
21
Answer:
Explanation:
a = kx
a= dv/dt = [dv/dx]*[dx/dt]
a = vdv/dx
vdv = adx
vdv = kxdx
v^2/2 = k*x^2/2 + C
as at t = 0 , x = 0 and velocity = u
so C = u^2/2
v^2/2 = kx^2/2 + u^2/2
v^2 = u^2 + kx^2
Answered by
0
Answer:
v^2 = u^2 + kx^2
Explanation:
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