A The length of a rod is 4x+5y−3z cm and the length of another is 6x−3y+z cm. By how much is the second rod longer than the first?
Answers
Answer:2x - 8y + 4z
Step-by-step explanation:The length of the first rod = 4x + 5y - 3z cm
The length of the second rod = 6x - 3y + z cm
Now, simply subtract them with the instruction of the question :
6x - 3y + z
4x + 5y - 3z
(-) (-) (+) ( Signs change )
_____________
2x - 8y + 4z
_____________
Therefore.. your answer is : 2x - 8y + 4z
Given:
The length of the first rod (L1) = 4x + 5y - 3x cm.
Lenth of the second rod (L2) = 6x - 3y + z cm.
To Find:
L2 - L1
Solution:
The quantity in which the second rod is longer than the first one can be obtained by finding the difference between the lengths of both the rods (L2-L1).
L2 - L1 = (6x-3y+z) - (4x+5y-3z)
= 6x - 3y + z - 4x - 5y - (-3z)
= 6x - 3y + z - 4x - 5y + 3z
Rearranging,
L2 - L1 = (6x - 4x) + (-3y - 5y) + (z + 3z)
= (6-4)x + (-3-5)y + (1+3)z
L2 - L1 = 2x - 8y + 4z.
The second rod is longer than the first rod by 2x-8y+4z.