Question

a) The perimeter of a quadrant of a circle is 71.4 cm. Find its diameter.
[Take n = 3.14)​

Answer 1

Answer:

Here 2πr / 4 = 71.4 or, r = (4 × 71.4) / 2π = 285.6 / 6.28 = 45.48 [ taking π = 3.14]

Therefore r = 45.48 cm and the diameter of the circle is 2 × r = 90.96 cm. (ans)