Question

(a) The perimeter of a rectangle is 2x2
-2xy+4z2
. If its width is 4xy-x
2
-z
2
, find its length?

(b) The area of a rectangle is x3

-8x2+7. One of its sides is x-1. Find the size of the other?

Answer 1

Answer:

gd morng dear have an astronomical day ahead

how are you?

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Step-by-step explanation:

answer will be 22222222222

Answer 2

Step-by-step explanation:

A) in a rectangle adjacent sides means length and breadth ;

Let the length = 3x^2- 2y^2

Breadth= x^2+3xy

PERIMETER OF rectangle =2(l+b)

=2(3x^2-2y^2 + x^2+3xy)

=2(4x^2-2y^2+3xy)

=8x^2-4y^2+6xy

B)Area of rectangle A=x2+7x+12

Length L=x+3

Breadth B=?

Area of rectangle A=L×B

⇒x2+7x+12=(x+2)×B

⇒B=x+3x2+7x+12​

=2+322+7(2)+12​=530​

∴Breadth=6

mark me brainiest if it's correct