Question

(a) the present age of a father is three times the
age of his son. After 20 years, the age of the
father will become two times the age of his son .​

Answer 1

Answer:

Let the present age of son be x.

Present age of father=4x.

Now,

Ten year hence his father age will be 3 times his son.

A/q

\begin{gathered}4x + 10 = 3(x + 10) \\ 4x + 10 = 3x + 30 \\ 4x - 3x = 30 - 10 \\ x = 20\end{gathered}

4x+10=3(x+10)

4x+10=3x+30

4x−3x=30−10

x=20

So,

Son age is=20 years

And father age is=4×20=80 years

Step-by-step explanation:

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