Question

a. The price of an article is reduced by 10%. By how much per cent this value be increased to rest
it to its former value?​

Answer 1

Answer:

Let the price orgl=loo

when reduced=90

90 (loo+x)/loo=100

100+x=loox loo/90=1000/9=111 1/9

loo+x=11 1 1/9

x = 11 1/9%