Math, asked by mzhaider911, 30 days ago

(a) The probability that a vehicle entering the Luray Caverns has Canadian
license plates is 0.12; the probability that it is a camper is 0.28; and the
probability that it is a camper with Canadian license plates is 0.09. What is
the probability that
) A camper entering the Luray Caverns has Canadian license Plates.
(ii) A vehicle with Canadian license plates entering the Luray Caverns is a
camper.
(iii) A vehicle entering the Luray Caverns does not have Canadian plates or
is not a camper.
(b) Sketch the plane representing - 2x2
= -8
(c) Given the points (-4,8) and (6, -12):
(i) Determine the midpoint of the line segment connecting the points.
(ii) Determine the distance separating the two points.​

Answers

Answered by amitnrw
12

Given :   The probability that a vehicle entering the Luray Caverns has Canadian license plates is 0.12,

the probability that it is a camper is 0.28;  

probability that it is a camper with Canadian license plates is 0.09.

To Find : What is the probability that

1) A camper entering the Luray Caverns has Canadian license Plates.

(2) A vehicle with Canadian license plates entering the Luray Caverns is a

camper.

(3) A vehicle entering the Luray Caverns does not have Canadian plates or

is not a camper.​

Solution:

probability that

1) A camper entering the Luray Caverns has Canadian license Plates.  

= 0.12,

probability that

(3) A vehicle with Canadian license plates entering the Luray Caverns is a

camper.

=  camper with Canadian license plates /  Canadian license plates

= 0.09/ 0.12

= 9/12

= 3/4

= 0.75

probability that

A vehicle entering the Luray Caverns does not have Canadian plates or

is not a camper.​  1  -  P (  Canadian plates or camper)

P (  Canadian plates or camper) = 0.12 + 0.28  - 0.09  =  0.31

A vehicle entering the Luray Caverns does not have Canadian plates or

is not a camper.​  1  -  P (  Canadian plates or camper)

= 1 - 0.31

= 0.69

Learn More:

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Answered by ya0831941
0

Answer:

license plate is 0.12 the probability is 0.28

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