Math, asked by prathimab85, 2 months ago

A
The real roots of the equation |x2 +4x +3+2x+5=0 are
A) 4: -1+ 3 B) -4; -1-13 C)-6,-1​

Answers

Answered by Dhaarini22
1

Answer:

hy

Step-by-step explanation:

x2 +4x+3∣+2x+5=0

∣(x+1)(x+3)∣+2x+5=0

Now from the expression (x+1)(x+3), we can see that the expression is negative for values lying between −1 and −3.

hence, for values not lying between −1 and −3 we can write equation as x2 +6x+8=0

(x+2)(x+4)=0

x cannot be equal to −2 as x cannot lie between −1 and −3

∴x=−4

For values in the range of −3 to −1 we can write equation as −x2 −4x−3+2x+5=0

−x2 −2x+2=0

x2 +2x−2=0

x=  root 3 −1 is discarded since it lies outside the −3 to −1

So, x=−1−(root 3 ) and −4

Answered by venkateshwarlu66
1

Answer:

What is the quotient of 4 and r?

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