Question

A=The set of all natural numbers less than 5, B=The set of all prime numbers less than 5, C= the set of all even prime numbers then find AX(BnC).

Answer 1

Answer:

A×(B⋂C) = { (1,2) , (2,2) , (3,2) , (4,2) }

Solution:

Given :

A=The set of all natural numbers less than 5

B=The set of all prime numbers less than 5

C= the set of all even prime numbers

To find : A×(B⋂C)

Clearly ,

The given sets are in set builder form .

Thus,

The given set in roster form are as follow ;

A = { 1 , 2 , 3 , 4 }

B = { 2 , 3 }

C = { 2 }

Now,

=> B⋂C = { 2 , 3 } ⋂ { 2 }

=> B⋂C = { 2 }

Now,

=> A×(B⋂C) = { 1 , 2 , 3 , 4 } × { 2 }

=> A×(B⋂C) = { (1,2) , (2,2) , (3,2) , (4,2) }

Hence,

The required value of A×(B⋂C) is ;

{ (1,2) , (2,2) , (3,2) , (4,2) }