Question

a)The sum of radius of base and height of solid cylinder is 37 m. If the total surface area of

solid cylinder is 1628 m2, find:

i) Radius of its base.

ii) Cost of painting its total surface at the rate of ₹ 15.10 per square meter. answer fast​

Answer 1

1. tsa of cylinder=2πr(h+r)

1628m^2=2*22/7*r*37

r=1628*7/2*22*37

r=7m

therefore, radius of its base is 7m.

2. cost of per square metre=15.10 rupees

=1628*15.10

=24582.8 rupees

Answer 2

Given :-

• Radius + Height = 37 m
• Total Surface Area = 1628 m²

To find :-

1. Radius of base = ?
2. Cost of painting it at ₹ 15.10 per m²

Solution :-

We know that

TSA of cylinder = 2πr (r + h)

$: \implies \sf{1628 = 2 \times \dfrac{22}{7} \times r \big(37 \big)}$

$\dashrightarrow \: \: \sf{1628 = \dfrac{1628r}{7} }$

$\dashrightarrow \: \sf{1628r = 1628 \times 7}$

$\dashrightarrow \: \sf{r = \dfrac{ \cancel{1628} \times 7}{ \cancel{1628}} }$

$\dashrightarrow \: \boxed{ \bf{r = 7 \: m}}$

For finding the cost of painting it:

• 1 m² = Rs 15.10
• 1628 m² = ?

So the cost of painting would be

→ 1628 × 15.10

=「₹ 24582.8」

∴ Cost of painting = ₹ 24582.8