Question

a) The sum of squares of first n natural numbers is given by n(n+1)(2n+1). Find the
6
sum of squares of the first 10 natural numbers.​

Answer 1

Answer:

The sum of squares of first n natural numbers is given by

n(n+1)(2n+1)/6

sum of squares of the first 10 natural numbers.​ = 385

Step-by-step explanation:

Answer 2

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