Question

a) The sum of squares of first n natural numbers is given by n(n+1)(2n+1). Find the
6
sum of squares of the first 10 natural numbers.​

Answer 1

Answer:

a) The sum of squares of first n natural numbers

is given by n(n+1)(2n+1).

sum of squares of the first 10 natural numbers.

Step-by-step explanation:

so n(n+1)

n+n

2n+1

3n. 3n×10.

30n÷6. ans 5is natural number