A.The sum of three consecutive integers is 36.Find the numbers.
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Let the three consecutive integers be x , x +1 and x +2
given ,
x + (x + 1) + (x + 2) = 36
3x + 3 = 36
3(x + 1) = 36
x + 1 = 36/3
x + 1 = 12
x = 12 - 1
x = 11
x + 1 = 11 + 1 = 12
x + 2 = 11+ 2 = 13
Hence, the numbers are 11,12,13
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