Question

a) The sum of three consecutive integers is 36. What is the number?
b) Find the simple interest on Rs.8000 for 2 years at 5% per annum. Find the amount.

Answer 1

Answer :-

a) Let the numbers be x , x + 1 and x + 2.

Sum of the number = 36

→ x + x + 1 + x + 2 = 36

→ 3x + 3 = 36

→ 3x = 36 - 3

→ 3x = 33

→ x = 33 / 3

→ x = 11

Numbers = 11 , 12 and 12

b)

• P = Rs. 8000
• T = 2 years
• R = 5% p.a.

Simple interest = P × R × T / 100

Substituting the values :-

→ SI = 8000 × 2 × 5 / 100

→ SI = 80 × 2 × 5

→ SI = 800

Simple interest = Rs. 800

Answer 2

a) The sum of three consecutive integers is 36. What is the number?

Given

Sum of three consecutive integers is 36

Find

The numbers

Solution

Let the first number be x

Second number be x+1

Third number be x+2

The sum of this integers is 36

∴x+(x+1)(x+2)=36

∴x+x+1+x+2=36

∴3x+3=36

∴3x=36-3

∴3x=33

∴x=33/3

∴x=11

Hence the three numbers are 11,12 and 13..

__________________________

b) Find the simple interest on Rs.8000 for 2 years at 5% per annum. Find the amount.

Given

P=8000₹

R=5%

T/n=2 years

Find

Simple interest

Solution

By using formula SI=PRT/100

∴SI=8000×5×2/100

∴SI=80,000/100

∴SI=800

Hence Simple interest is 800₹