Question

a the volume, the lateral surface area and the total surface area of the cuboid whose dimensions are: length = 12 cm, breadth = 8 cm and height = 4.5 cm m length = 26 m, breadth = 14 m and height = 6.5 m m length = 15 m, breadth = 6 m and height = 5 dm liv) length = 24 m, breadth = 25 cm and height = 6 m​

Answer 1

Answer:

It is given that length =12 cm, breadth 8 cm and height =4.5cm

It is given that length =12 cm, breadth 8 cm and height =4.5cmWe know that

It is given that length =12 cm, breadth 8 cm and height =4.5cmWe know thatVolume of cuboid =l×b×h

It is given that length =12 cm, breadth 8 cm and height =4.5cmWe know thatVolume of cuboid =l×b×hVolume of cuboid =12×8×4.5

It is given that length =12 cm, breadth 8 cm and height =4.5cmWe know thatVolume of cuboid =l×b×hVolume of cuboid =12×8×4.5Volume of cuboid =432 cm

It is given that length =12 cm, breadth 8 cm and height =4.5cmWe know thatVolume of cuboid =l×b×hVolume of cuboid =12×8×4.5Volume of cuboid =432 cm 3

It is given that length =12 cm, breadth 8 cm and height =4.5cmWe know thatVolume of cuboid =l×b×hVolume of cuboid =12×8×4.5Volume of cuboid =432 cm 3

It is given that length =12 cm, breadth 8 cm and height =4.5cmWe know thatVolume of cuboid =l×b×hVolume of cuboid =12×8×4.5Volume of cuboid =432 cm 3 We know that

It is given that length =12 cm, breadth 8 cm and height =4.5cmWe know thatVolume of cuboid =l×b×hVolume of cuboid =12×8×4.5Volume of cuboid =432 cm 3 We know thatLateral surface of a cuboid =2(l+b)×h

It is given that length =12 cm, breadth 8 cm and height =4.5cmWe know thatVolume of cuboid =l×b×hVolume of cuboid =12×8×4.5Volume of cuboid =432 cm 3 We know thatLateral surface of a cuboid =2(l+b)×hLateral surface area of a cuboid =2(12+8)×4.5

It is given that length =12 cm, breadth 8 cm and height =4.5cmWe know thatVolume of cuboid =l×b×hVolume of cuboid =12×8×4.5Volume of cuboid =432 cm 3 We know thatLateral surface of a cuboid =2(l+b)×hLateral surface area of a cuboid =2(12+8)×4.5Lateral surface area of a cuboid =2×20×4.5

It is given that length =12 cm, breadth 8 cm and height =4.5cmWe know thatVolume of cuboid =l×b×hVolume of cuboid =12×8×4.5Volume of cuboid =432 cm 3 We know thatLateral surface of a cuboid =2(l+b)×hLateral surface area of a cuboid =2(12+8)×4.5Lateral surface area of a cuboid =2×20×4.5Lateral surface area of a cuboid =180cm

It is given that length =12 cm, breadth 8 cm and height =4.5cmWe know thatVolume of cuboid =l×b×hVolume of cuboid =12×8×4.5Volume of cuboid =432 cm 3 We know thatLateral surface of a cuboid =2(l+b)×hLateral surface area of a cuboid =2(12+8)×4.5Lateral surface area of a cuboid =2×20×4.5Lateral surface area of a cuboid =180cm 2

It is given that length =12 cm, breadth 8 cm and height =4.5cmWe know thatVolume of cuboid =l×b×hVolume of cuboid =12×8×4.5Volume of cuboid =432 cm 3 We know thatLateral surface of a cuboid =2(l+b)×hLateral surface area of a cuboid =2(12+8)×4.5Lateral surface area of a cuboid =2×20×4.5Lateral surface area of a cuboid =180cm 2

It is given that length =12 cm, breadth 8 cm and height =4.5cmWe know thatVolume of cuboid =l×b×hVolume of cuboid =12×8×4.5Volume of cuboid =432 cm 3 We know thatLateral surface of a cuboid =2(l+b)×hLateral surface area of a cuboid =2(12+8)×4.5Lateral surface area of a cuboid =2×20×4.5Lateral surface area of a cuboid =180cm 2 We know that

It is given that length =12 cm, breadth 8 cm and height =4.5cmWe know thatVolume of cuboid =l×b×hVolume of cuboid =12×8×4.5Volume of cuboid =432 cm 3 We know thatLateral surface of a cuboid =2(l+b)×hLateral surface area of a cuboid =2(12+8)×4.5Lateral surface area of a cuboid =2×20×4.5Lateral surface area of a cuboid =180cm 2 We know that Total surface area of cuboid =(Ib+bh+Ih)

It is given that length =12 cm, breadth 8 cm and height =4.5cmWe know thatVolume of cuboid =l×b×hVolume of cuboid =12×8×4.5Volume of cuboid =432 cm 3 We know thatLateral surface of a cuboid =2(l+b)×hLateral surface area of a cuboid =2(12+8)×4.5Lateral surface area of a cuboid =2×20×4.5Lateral surface area of a cuboid =180cm 2 We know that Total surface area of cuboid =(Ib+bh+Ih)Total surface area of cuboid =2(12××8+8×4.5+12×4.5)

It is given that length =12 cm, breadth 8 cm and height =4.5cmWe know thatVolume of cuboid =l×b×hVolume of cuboid =12×8×4.5Volume of cuboid =432 cm 3 We know thatLateral surface of a cuboid =2(l+b)×hLateral surface area of a cuboid =2(12+8)×4.5Lateral surface area of a cuboid =2×20×4.5Lateral surface area of a cuboid =180cm 2 We know that Total surface area of cuboid =(Ib+bh+Ih)Total surface area of cuboid =2(12××8+8×4.5+12×4.5)Total surface area of cuboid =2(96+36+54)

It is given that length =12 cm, breadth 8 cm and height =4.5cmWe know thatVolume of cuboid =l×b×hVolume of cuboid =12×8×4.5Volume of cuboid =432 cm 3 We know thatLateral surface of a cuboid =2(l+b)×hLateral surface area of a cuboid =2(12+8)×4.5Lateral surface area of a cuboid =2×20×4.5Lateral surface area of a cuboid =180cm 2 We know that Total surface area of cuboid =(Ib+bh+Ih)Total surface area of cuboid =2(12××8+8×4.5+12×4.5)Total surface area of cuboid =2(96+36+54) Total surface area of cuboid =2×186

By multiplying this 2x186 we get answer 372

Step-by-step explanation:

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Answer 2

Answer:

1.volume=l×b×h=12×8×4.5=432sq.cm

Step-by-step explanation:

2.lateral surface area=2(l+b)h,2(12+8)4.5=2×20×4.5=180sq.cm

total S.A=2(lb+bh+lh)=2(12×8+8×4.5+12×4.5)=2(96+36+54)=2×186=392sq.vm