Question

A theater can hold 140 giants or 210 elves. If 90 giants are already inside, how many elves can also be admitted?

Answer 1

Answer:

refer the attachment

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Answer 2

$It \: is \: given \: that,$

$A \: theatre \:can \:hold \: 140 \:gaints\: or$

$210 \: elves$

/* According to the problem given */

$If \: 90 \: gaints\: are \: already \: inside$

$Let \: number \: of \: elves \: admitted = x$

$\implies 140 : 210 = 90 : x$

$product \:of \: extremes = product \:of \:means$

$\implies 140 \times x = 210 \times 90$

$\implies x = \frac{210 \times 90}{140}$

$\implies x = 3 \times 45$

$\implies x = 135$

Therefore.,

$\red{number \: of \: elves \: admitted }\green { = 135}$

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