Question

. a theif is running with a speed 10m/s and when he is 10.5 m ahead of a police jeep it starts chasing him with an accelaration 1m/s2 starting from rest when and where the police catch the theif​

Answer 1

Answer:The acceleration of thief relative to the poilce is a−0=a. Initial velocity of thief relative to the police is 0−v=−v. Initial distance of thief relative to the police is x. Final distance of theif relative to police = 0.

Relative displacement of theif relative to police, s=0−x=−x

Applying Newton's third law of motion,  

v  

f

​  

 

2

=v  

2

−2ax

If the police can catch the theif, v  

f

​  

 is a real number and hence v  

f

​  

≥0

Hence, v  

2

≥2ax

Explanation: