A theif
run at the uniform speed 100m/min and a policeman run behind the theif after one minute the speed of policeman is 100m/min and increasing 10m/min in every minute find in how many minute policeman will caught the theief
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Answered by
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Speed of thief(s) = 100 m/min
speed of police man (u)=100 m/min
acceleration(a) = 10 m/min^2
Let's assume that the policeman catches the thief after t minutes
then time for policeman = t min
time for thief = (t+1) min
Distance travelled by policeman = Distance travelled by thief
=> ut + 1/2 at^2 = st
=> 100t + 1/2 × 10 × t^2 = 100(t+1)
=> 100t + 5t^2 = 100t + 100
=> 5t^2 = 100t - 100t + 100
=> 5t^2 = 100
=> t^2 = 100/5 = 20
=> t =.√20 = 2√5 seconds.
So the policeman will take 2√5 minutes = 2×2.24 = 4.48seconds
speed of police man (u)=100 m/min
acceleration(a) = 10 m/min^2
Let's assume that the policeman catches the thief after t minutes
then time for policeman = t min
time for thief = (t+1) min
Distance travelled by policeman = Distance travelled by thief
=> ut + 1/2 at^2 = st
=> 100t + 1/2 × 10 × t^2 = 100(t+1)
=> 100t + 5t^2 = 100t + 100
=> 5t^2 = 100t - 100t + 100
=> 5t^2 = 100
=> t^2 = 100/5 = 20
=> t =.√20 = 2√5 seconds.
So the policeman will take 2√5 minutes = 2×2.24 = 4.48seconds
kamaljyala642135:
Wrong bro this question is of AP
correct answer
bhai ans minute m aaega..
It's the wrong answer...
bhai jabardast answer
Yes, answer minute mein ayega, lekin answer galat nahin hai... answer is 2√5 minutes
@Kamal If you take it as an AP question, you are assuming that the speed increases by 10meters/minute instantly at the end of one minute. That's not the case. So you will get wrong answer
Answered by
0
Answer:
above is the right answer
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