A theif steals a car at 1.30 p.m and drivers it at 40km.an hour.The theft is discovered at 2.p.m and the owner sets off in another car at 50km an hour.he will overtake the theif at
Answers
Answered by
1
relative velocity of the police with respect to the thief =10km(50-40)km/hr
and the distance covered by the thief in 1/2an hour=40×1/2=20 km.
again the time taken by the police to catch or overtake the thief is 20/10=2 hrs.
and the distance covered by the thief in 1/2an hour=40×1/2=20 km.
again the time taken by the police to catch or overtake the thief is 20/10=2 hrs.
Answered by
2
theif cover distance in half a hour=20
owner cover in 1hour=50 and theif cover 20+40=60
next one hour owner cover 50+50=100km
theif cover next one over=60+40=100
so owner over take theif in 2hours
owner cover in 1hour=50 and theif cover 20+40=60
next one hour owner cover 50+50=100km
theif cover next one over=60+40=100
so owner over take theif in 2hours
Similar questions