Question

A thermal power plant has input energy consumption of 100 KJ and generates output energy of 30 KJ. The overall efficiency of this thermal power plant is
1 point
70%
45%
30%
15%

Answer 1

Answer:

30 percent

Explanation:

not sure I think because it produces 30 kj from 100 kj that is 30 percent

Answer 2

Given:

Input energy consumption = 100kJ

Output energy consumption = 30kJ

Find:

The overall percentage efficiency of the powerplant

Solution:

The efficiency of the power plant is given by the formula:

efficiency = (output / input) * 100

putting the values of output and input in the above formula we get,

efficiency = (30kJ / 100kJ) * 100

                 =  0.3 * 100 = 30%

The overall percentage efficiency of Thermal powerplant is 30%