A thermocouple ammeter give full scale deflection at10 a when the meter reads one fifth of the scale the current will be
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0
Answer:
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Answered by
1
Answer:
4.47
Explanation:
Q1/Q2 = I1^2/I2^2
5/1 = 10^2/I2^2
I2^2 = 100/5
I2 = √100/5
I2 = 4.47
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