A thermodynamic system is taken from an original state to an intermediate state by the linear process shown in Fig. (12.13) Its volume is then reduced to the original value from E to F by an isobaric process. Calculate the total work done by the gas from D to E to F.
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Here's , Your Answer :-
=) We know , Total work done by the gas from D to E to F = Area of ΔDEF
Area of ΔDEF = (1/2) DE × EF
Where,
DF = Change in pressure
= 600 N/m^2– 300 N/m^2
= 300 N/m^2
FE = Change in volume
= 5.0 m^3 – 2.0 m^3
= 3.0 m^3
Area of ΔDEF = (1/2) × 300 × 3
= 450 J. (ans.)
Therefore, the total work done by the gas from D to E to F is 450 Joules .
_________________________
_________________________
HOPE , IT HELPS ... ✌️
___________________________
___________________________
Here's , Your Answer :-
=) We know , Total work done by the gas from D to E to F = Area of ΔDEF
Area of ΔDEF = (1/2) DE × EF
Where,
DF = Change in pressure
= 600 N/m^2– 300 N/m^2
= 300 N/m^2
FE = Change in volume
= 5.0 m^3 – 2.0 m^3
= 3.0 m^3
Area of ΔDEF = (1/2) × 300 × 3
= 450 J. (ans.)
Therefore, the total work done by the gas from D to E to F is 450 Joules .
_________________________
_________________________
HOPE , IT HELPS ... ✌️
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