Question

A thermodynamic system is taken from an original state to an intermediate state by the linear process shown in the figure. Its volume is then reduced to the original value from E to F by an isobaric process. Calculate the total work done by the gas from D to E to F.

Answer 1

Answer:-

From the above figure, we know that the total work done by the gas from A to B to C = Area of triangle ABC.

Now,

Area of triangle ABC = $\frac{1}{2}$ × AC × BC

Where,

AC = Change in pressure and BC = Change in volume

Now,

AC = (800 – 400) N/m² = 400 N/m²

And, BC = (7 – 3) m³ = 4 m³

Now,

The Area of triangle ABC = $\dfrac{1}{2}\times AC \times BC$

$\implies \frac{1}{2} \times 400 \times 4 = 800J$

Therefore, the Total work done by the gas from A to B to C is 800 J.