Question

A thermometer has 20 equal divisions between 90℃ and 100℃ marks. A student while determining the boiling point of water finds the mercury thread become stationary at the 19th mark above 90℃.He should record the correct boiling point as a)90.19℃ b) 99.5℃ c) 100℃ d) 100.19℃

Answer 1

Letter b The answer is 99.5C
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Answer 2

Length of each division =

$\frac{100 - 90}{20} = \frac{10}{20} = 0.5$

Temperature corresponding to 19th division is given by

$90 + 19 \times 0.5 = 90 + 9.5 = 99.5$

Therefore, the temperature corresponding to 19th division is 99.5℃ i.e. Option (b)