A thermometer is made such that the freezing point of water is defined to be 60.0°H and the boiling point of water at sea level is defined to be 520°H. What is absolute zero on the H scale?
A) -36°H
B) -980°H
C) -1196°H
D)0.6°H
E)-1256°H
Answers
Answer:
here is your answer
a is correct answer of this question
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Concept:
The change in scale with respect to the actual scale can be determined by comparing it with the known temperatures.
Given:
Here, the freezing point of water is defined to be 60.0°H and the boiling point of water at sea level is defined to be 520°H in the defined thermometer.
Find:
The absolute zero on this scale.
Solution:
Here, in the newly defined thermometer, the freezing point is 60 °H which is 273 K in absolute temperature and the boiling point is 520 °H which is 373 K in absolute temperature.
Comparing with the known temperatures,
(K-273/H-60) = (373-273)/ (520-60)
The value of K is substituted to 0, as we have to calculate the absolute zero.
(0-273/H-60) = (373-273)/ (520-60)
-273/(H-60)= 0.217
(H-60)= -273/0.217 = -1258 °H
H= -1258+60 = - 1198 °H ≈ -1196°H
Hence, the absolute zero in the defined H scale is -1196°H. Hence, the correct option is (C) -1196°H.
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