A thick rope of density p and length 1 is hung from a rigid support. The
young's modulus of the material of rope is Y. The increase in length of
the rope due to its own weight is
1)
2) pgl/Y
pgl/Y
4) pgl/Y
1) pgl /Y
3)
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Answer:
Correct option is
B
2Y
1
ρL
2
g
Take a small section δy at distance y from top as shown in figure. Let area of rope be A
Stress due to this section = ρAgδy/A=ρdδy
Strain on section y = δl/y
Using Stress = Y \times Strain
=> ρgδy=Y×
y
δl
=>Δl=
y
ρg
∫
0
L
yδy
=> Δl=
2Y
ρgL
2
Answer.
2Y
ρgL
2
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