Question

A thick straight wire of length a m is fixed at
its midpoint and then bent in the form of a
circle. The shift in its centre of mass is
ubr
1) am
2) 0.5 m
3) 2 m
4)pie divided by 2



I want to know the method I know the answer.
I will mark you as the brainliest

Please help me with this question.................:)

Answer 1

Answer:

cc'= radius= shift

length of rod = l

therefore, circumference of circle = l

2πr= l

r= l/2π

Answer 2

Answer: 0.5

Explanation:

In this the shift in CM is equal to radius of the circle formed

So 2πR = l

R = l/2π

Where l is equal to π

So R=π/2π

R=0.5