Question

a thick uniform rope of mass 6 kg and length 3 metre is having vertically from a rigid support .the tension of the Rope at the point 1m from the support Will be​

Answer 1

Answer:

It will be 20N.

Explanation:

since it's a rope we will calculate the mass per unit length .

given mass m=6 kg

given length l= 3 m

therefore m/l= 2kg/m

hence the mass of the rope at 1m from the support will be m/l *1= 2kg/m *1m= 2kg

therefore the force of tension will be =mass*g=2*10=20N

Answer 2

Answer:20N.

Explanation:

The force is uniformly distributed over the mass of the rope. So the tension action at point A will be the total force acting on the left part of the rope from point A because this point will be pulling it's left part ,So tension T at point A is T=F(1−xL).

given:

mass m=6 kg

length l= 3 m

∴ m/l= 2kg/m

mass of the rope at 1m from the support will be m/l *1= 2kg/m *1m= 2kg

force of tension will be =mass*g=2*10=20N

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