A thief escapes from jail and runs at a speed of 5m / min. Police start running after him after 2min. If police speed increases by one m per minute, how long after the police catch the thief
Answers
Answer:
Answer
According to the question,
Distance between thief and police after 2 minutes = 100 m
Police starts chasing thief with initial speed of 60 and increasing his speed by 5 m every minute.
Let the police chase the thief for t minutes.
Implies, thief covers total 100 + 50t m
Police runs with following pattern 60,65,70...
This is an Arithmetic Progression with a = 60, d = 5 & number of terms = t
t/2(2×60+(t−1)×5)=50t+100
t×(120+5t−5)=100t+200
5t
2
+15t−200=0
t
2
+3t−40=0
t={−3±
(9+160)}/2
=(−3±13)/2=+5
Implies, police will catch thief in 5 minutes.
Answer:
Mark Me As Brainliest
Step-by-step explanation:
According to the question,
Distance between thief and police after 2 minutes = 100 m
Police starts chasing thief with initial speed of 60 and increasing his speed by 5 m every minute.
Let the police chase the thief for t minutes.
Implies, thief covers total 100 + 50t m
Police runs with following pattern 60,65,70...
This is an Arithmetic Progression with a = 60, d = 5 & number of terms = t
t/2(2×60+(t−1)×5)=50t+100
t×(120+5t−5)=100t+200
5t
2
+15t−200=0
t
2
+3t−40=0
t={−3±
(9+160)}/2
=(−3±13)/2=+5
Implies, police will catch thief in 5 minutes.