a thief is ascaping with avelocity of 54km/h and the policeman follows him with 72km/h. if the gap b/w the policeman and the thief is 10km/h . how much time the thief will be caught
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Answer:
Relative Velocity of the Policeman = (72 - 54) km/hr
= 18 km/hr
= 5 m/s
∴ Time required = 10000/5 s
= 2000 s
=33 mins. 20 seconds.
Explanation:
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