Question

A thief is running on a motorcycle at a constant speed
of 25 ms-1. A police jeep starts chasing from a point
1.25 km behind him with a uniform acceleration of 2
ms-2
what should be the minimum acceleration of the thief to escape from the police​

Answer 1

Answer:

The relative velocity of policeman w.r.t. thief

=10−9=1 ms

−1

∴ Time taken by police to catch the thief

=

velocity

distance

=

1

100

=100 s.