A thief is running on a motorcycle at a constant speed of 25m/s. A police jeep starte
chasing from a point 1.25 km behind him with a uniform acceleration of 2m/s2.
a) After how much time will the police catch the thief?
b) How much distance will the jeep cover to reach the thief?
c) What should be the minimum acceleration of the thief to escape from police?
Class 11 physics
Plzzzz answer fast its urgent!!!
Answers
Answered by
9
Answer:
police will catch the thief if distance travel by policein time t=1250m.+25t m.
using s=ut+1/2 at^2
u=0,a=2m.s^2
(1/2)*2 t^2=1250+25t
t^2-25t-1250=0
(t+25)(t-50)=0
so t=50 sec.
aviacc:
Thanks but plzz answer the subdivisions B and C
Answered by
7
Answer:
1250m
Explanation:
Use the second equation of motion fir the second part put t=50 and a=2
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