Math, asked by naman112iscool, 8 months ago

A thief is running with speed of 25 m/s on a straight road, a policeman sees him and starts chasing him with constant acceleration of 6m/s² if initial gap between them then was 50m policeman will catch the thief in

Answers

Answered by pinjaraarifisha

1

The relative velocity of policeman w.r.t. thief

=10−9=1 ms ^−1

∴ Time taken by police to catch the thief

= distance / velocity

= 100 / 1

=100 s.

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Answered by devasapkale

0

Answer:

The relative velocity of policeman w.r.t. thief

=10−9=1 ms

−1

∴ Time taken by police to catch the thief

=

velocity

distance

=

1

100

=100 s.

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