A thief is spotted by a policeman from a distance of 200 metre. when the policeman starts chasing , the thief also starts running. if the speed of the thief be 16kmph and that of policeman be 20kmph, how far the thief will have run before he is overtaken?
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d = 200 m, a = 16kmph = 40/9 m/s, b = 20kmph = 50/9 m/s
Required Distance D = d*(a/b-a)b= 200*(40/9/10/9) = 800m
Required Distance D = d*(a/b-a)b= 200*(40/9/10/9) = 800m
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