A thief is spotted by a policeman from a distance of 255m. When the policeman starts chasing, the thief also starts running. If the speed of the thief be 12 km/h and that of the policeman be 16 km/h, how far the thief will have run before he is overtaken?
Answers
Answer:
x = 3×255 =
Step-by-step explanation:
See the image.
Let (x) be the distance travelled by thief. Then the distance covered by policeman is ( 255 + x ). Since the times would be same and time = speed ÷ distance.....( See the image). That is 's' not '5'. Please mark as brainliest.
The distance run by the thief before he is overtaken = 765m
Given :
The distance between the policeman and the thief = 255m
Speed of the thief = 12km/h
Speed of the policeman = 16km/h
To find :
The distance the thief runs before he is overtaken
Solution :
The speed of the thief = 12km/h
The speed of the policeman = 16km/h
Therefore, their relative speed = 16km/h - 12km/h = 4km/h
The time the policeman takes to overtake the thief
= Distance between the thief and policeman / Their relative speed
= 255m / 4km/h = 255m / (4km/h x 5/18) = 229.5s
The distance the thief travels in 229.5s
= 229.5s x Speed of the thief
= 229.5s x 12km/h x 5/18 = 765m
The distance run by the thief before he is overtaken = 765m
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